sql語句拼接
sql語句拼接主要操作于有條件的的增加,刪除,修改或查詢,下面給你介紹一個條件查詢的例子:
既然是拼接sql語句長度不一定,用StringBuffer修飾,而不用String
String name=*ameter("name");
String address=*emeter("address");
StringBuffer sql = new StringBuffer();
*("select * from Tuser as t where 1=1");
if(name!=null||!"".equals(name)){
*(" and * like'%"+name+"%'");
}
if(address!=null||!"".equals(address)){
*(" and *s like'%"+address+"%'");
}
以上就是拼接sql語句,也就是說select * from Tuser as t where 1=1一定會執行,而后面兩個會根據用戶數據參數選擇執行
我可是手寫的啊,沒有復制,明白了嗎?不明了再問我,明白了就給分吧,嘿嘿
拼接SQL語句
sql語句拼接主要操作于條件增加刪除修改或查詢面給介紹條件查詢例:
既拼接sql語句度定用StringBuffer修飾用String
String name=*ameter("name");
String address=*emeter("address");
StringBuffer sql = new StringBuffer();
*("select * from Tuser as t where 1=1");
if(name!=null||!"".equals(name)){
*(" and * like'%"+name+"%'");
}
if(address!=null||!"".equals(address)){
*(" and *s like'%"+address+"%'");
}
拼接sql語句說select * from Tuser as t where 1=1定執行面兩根據用戶數據參數選擇執行
我手寫啊沒復制明白明再問我明白給吧嘿嘿!
sql語句拼接問題
你網頁是用什么語言寫的呀?
簡單的寫法, 就是
string sql = "SELECT * FROM 商品表 WHERE 1=1 "
if ( 畫面上面的 品牌輸入了 )
sql = sql + " AND 品牌 = '" + 畫面上面輸入的品牌 + "'";
if ( 畫面上面的 價格輸入了 )
sql = sql + " AND 價格 between " + 畫面上面輸入的最低價格 + " and " + 畫面上面輸入的最高價格 ;
執行 sql 語句
顯示查詢結果
兩個sql語句拼接
select *,*,*, *,*,* from formtable_main_32 m ,(
select id,mc,gjc from (select id,mc mc,ywgjz gjc from formtable_main_23 where cyfl = 4 union
select id,tzr mc,tzrxssjg gjc from formtable_main_23 where cyfl = 0 union
select id,Yfjsfzr mc,Yfxx gjc from formtable_main_23 where cyfl = 1 union
select id,Lshi mc,Lsuo gjc from formtable_main_23 where cyfl = 2 union
select *,Rczw mc,*name gjc from formtable_main_23 a left join workflow_SelectItem b on * = *value where cyfl = 3 and fieldid = 6212) as tmp) tm where *=*
SQL語言拼接
問題說的不太明白,看了追問才猜出大概意思~~~~~~~~~~
解決思路是這樣:查詢中增加一列自增列,在此基礎上再增加一列分組列(為自增列除2取整),然后用group by以分組列對其分組查詢,語句如下:(未經測試,如遇問題,繼續追問)
select groupID FID,min(FlnputTime) FlnputTime,min(FNumber) FNumber,avg(FGrating_1) FGrating_1,avg(FGrating_2) FGrating_2,avg(FGrating_3) FGrating_3,avg(FGrating_4) FGrating_4,avg(FGrating_5) FGrating_5,avg(FGrating_6) FGrating_6,avg(FGrating_7) FGrating_7,avg(FGrating_8) FGrating_8 into std from (select flood(**2) groupID,* from (select identity(int,1,1) sn,* from stu)) group by groupID
多條sql語句如何拼接
SQL語句拼接一般使用【union all】和【union】
兩者的區別是:
【union all】:顯示多條語句里的全部記錄;
【union】:顯示多條語句里的不重復的記錄,也就是有DIstinct的功效;
【union all】示例:
select '2016-02-06' date_time union all
select '2016-02-14' union all
select '2016-06-12' union all
select '2016-09-18' union all
select '2016-10-09' union all
select '2016-10-09'結果為6行
【union】示例:
select '2016-02-06' date_time union all
select '2016-02-14' union all
select '2016-06-12' union all
select '2016-09-18' union all
select '2016-10-09' union all
select '2016-10-09'結果為5行
三條SQL語句 拼接在一起 顯示出來
用Union ALL :
select *, *, 人數=COUNT(*) from T_Student tsd,T_School tsl where *=* group by * ,* -- (學校人數統計)
Union ALL
select *, *on, 人數=COUNT(*) from T_Student tsd,T_Position tst where *=* group by * ,*on --(城市人數統計)
Union ALL
select *, *on, 學校個數=COUNT(*) from T_School sch,T_Position pon where *=* grou